![]() ![]() Now, instead of solving this manually, let us apply the keyword approach to solve this question. Thus, we can have only 3 doubles teams from 3 players. Let us understand the concept of combination by solving example 1- “ From 3 players, A, B, and C, how many doubles team can be formed?”įrom 3 players A, B, and C, the teams of 2-players can be: ![]() This simple example clearly shows that the understanding of combination and permutation can help to decide when arrangement matters and when selection matters. But, in the second case, the arrangement of the letters can give us two different words. O Thus, in the first case, arrangement of the “team members” does not affect the team composition. While, in example 2, the word AB is not same as word BA.In example 1, the team (A B) is same as the team (B A).From 3 letters, A, B, and C, how many 2-digit words can be formed?ĭo both the examples looks same to you? From 3 players, A, B, and C, how many doubles team can be formed?Ģ. To clarify this confusion, let us understand two simple cases:ġ. In most of the p and c questions, we arrive at a point where we need to select or arrange a few things and many students fall prey to the same mistake of applying selection in place of arrangement and vice-versa. We will also provide few GMAT like practice questions to test the understanding. How to visualize a permutation and combination question if keywords are not given.Keyword approach to identify the combination or permutation type of questions. ![]()
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